3/4(2x-1)-5=2/3(x

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Solution for 3/4(2x-1)-5=2/3(x equation: 



3/4(2x-1)-5=2/3(x

We move all terms to the left:

3/4(2x-1)-5-(2/3(x)=0



Domain of the equation: 4(2x-1)!=0

x∈R





Domain of the equation: 3x-5!=0

We move all terms containing x to the left, all other terms to the right

3x!=5

x!=5/3

x!=1+2/3

x∈R



We calculate fractions


(9x-5)/(24x^2-12x-5)+(-8x2/(24x^2-12x-5)=0



We calculate terms in parentheses: +(-8x2/(24x^2-12x-5), so:

-8x2/(24x^2-12x-5

We multiply all the terms by the denominator


-8x2

We add all the numbers together, and all the variables

-8x^2

Back to the equation:

+(-8x^2)



We get rid of parentheses

-8x^2+(9x-5)/(24x^2-12x-5)=0

We multiply all the terms by the denominator


-8x^2*(24x^2-12x-5)+(9x-5)=0

We get rid of parentheses

-8x^2*(24x^2-12x-5)+9x-5=0

We move all terms containing x to the left, all other terms to the right

-8x^2*(24x^2-12x-5)+9x=5

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