3/4(2x-1)-5=2/3(x+1)

Solution for 3/4(2x-1)-5=2/3(x+1) equation:

3/4(2x-1)-5=2/3(x+1)

We move all terms to the left:

3/4(2x-1)-5-(2/3(x+1))=0


Domain of the equation: 4(2x-1)!=0

x∈R



Domain of the equation: 3(x+1))!=0

x∈R


We calculate fractions


(9xx/(4(2x-1)*3(x+1)))+(-8x2/(4(2x-1)*3(x+1)))-5=0


We calculate terms in parentheses: +(9xx/(4(2x-1)*3(x+1))), so:

9xx/(4(2x-1)*3(x+1))

We multiply all the terms by the denominator


9xx

Back to the equation:

+(9xx)



We calculate terms in parentheses: +(-8x2/(4(2x-1)*3(x+1))), so:

-8x2/(4(2x-1)*3(x+1))

We multiply all the terms by the denominator


-8x2

We add all the numbers together, and all the variables

-8x^2

Back to the equation:

+(-8x^2)


We get rid of parentheses

-8x^2+9xx-5=0

We move all terms containing x to the left, all other terms to the right

-8x^2+9xx=5