3/4(2x-5)+1/6(x+7)=2/3(x-2)

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Solution for 3/4(2x-5)+1/6(x+7)=2/3(x-2) equation: 



3/4(2x-5)+1/6(x+7)=2/3(x-2)

We move all terms to the left:

3/4(2x-5)+1/6(x+7)-(2/3(x-2))=0



Domain of the equation: 4(2x-5)!=0

x∈R





Domain of the equation: 6(x+7)!=0

x∈R





Domain of the equation: 3(x-2))!=0

x∈R



We calculate fractions

We do not support expression: x^22

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