3/4(2x-5)+3/2=2/8(7-3x)

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Solution for 3/4(2x-5)+3/2=2/8(7-3x) equation: 



3/4(2x-5)+3/2=2/8(7-3x)

We move all terms to the left:

3/4(2x-5)+3/2-(2/8(7-3x))=0



Domain of the equation: 4(2x-5)!=0

x∈R





Domain of the equation: 8(7-3x))!=0

x∈R



We add all the numbers together, and all the variables

3/4(2x-5)-(2/8(-3x+7))+3/2=0

We calculate fractions


(48x(-)/(4(2x-5)*8(-3x+7))*2)+(-(2*4(2x-5)*2)/(4(2x-5)*8(-3x+7))*2)+(96x^22/(4(2x-5)*8(-3x+7))*2)=0



We calculate terms in parentheses: +(48x(-)/(4(2x-5)*8(-3x+7))*2), so:

48x(-)/(4(2x-5)*8(-3x+7))*2

We add all the numbers together, and all the variables

48x0/(4(2x-5)*8(-3x+7))*2

We multiply all the terms by the denominator


48x0

We add all the numbers together, and all the variables

48x

Back to the equation:

+(48x)





We calculate terms in parentheses: +(-(2*4(2x-5)*2)/(4(2x-5)*8(-3x+7))*2), so:

-(2*4(2x-5)*2)/(4(2x-5)*8(-3x+7))*2

We multiply all the terms by the denominator


-(2*4(2x-5)*2)



We calculate terms in parentheses: -(2*4(2x-5)*2), so:

2*4(2x-5)*2

Wy multiply elements

16x(2

Back to the equation:

-(16x(2)



Back to the equation:

+(-(16x2)





We calculate terms in parentheses: +(96x^22/(4(2x-5)*8(-3x+7))*2), so:

96x^22/(4(2x-5)*8(-3x+7))*2

We do not support expression: x^22

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