3/4(2x-6)+1/2=2/5(3x+20)

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Solution for 3/4(2x-6)+1/2=2/5(3x+20) equation: 



3/4(2x-6)+1/2=2/5(3x+20)

We move all terms to the left:

3/4(2x-6)+1/2-(2/5(3x+20))=0



Domain of the equation: 4(2x-6)!=0

x∈R





Domain of the equation: 5(3x+20))!=0

x∈R



We calculate fractions


(30x3/(4(2x-6)*5(3x+20))*2)+(-(2*4(2x-6)*2)/(4(2x-6)*5(3x+20))*2)+(20x^22/(4(2x-6)*5(3x+20))*2)=0



We calculate terms in parentheses: +(30x3/(4(2x-6)*5(3x+20))*2), so:

30x3/(4(2x-6)*5(3x+20))*2

We multiply all the terms by the denominator


30x3

We add all the numbers together, and all the variables

30x^3

We do not support expression: x^3

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