3/4(36x+16)-1=-1/3(12x-12)

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Solution for 3/4(36x+16)-1=-1/3(12x-12) equation: 



3/4(36x+16)-1=-1/3(12x-12)

We move all terms to the left:

3/4(36x+16)-1-(-1/3(12x-12))=0



Domain of the equation: 4(36x+16)!=0

x∈R





Domain of the equation: 3(12x-12))!=0

x∈R



We calculate fractions


(9x1/(4(36x+16)*3(12x-12)))+(-(-4x3)/(4(36x+16)*3(12x-12)))-1=0



We calculate terms in parentheses: +(9x1/(4(36x+16)*3(12x-12))), so:

9x1/(4(36x+16)*3(12x-12))

We multiply all the terms by the denominator


9x1

We add all the numbers together, and all the variables

9x

Back to the equation:

+(9x)





We calculate terms in parentheses: +(-(-4x3)/(4(36x+16)*3(12x-12))), so:

-(-4x3)/(4(36x+16)*3(12x-12))

We add all the numbers together, and all the variables

-(-4x^3)/(4(36x+16)*3(12x-12))

We multiply all the terms by the denominator


-(-4x^3)

We do not support expression: x^3

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