3/4(3m+4)=2/3(6m+8)

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Solution for 3/4(3m+4)=2/3(6m+8) equation: 



3/4(3m+4)=2/3(6m+8)

We move all terms to the left:

3/4(3m+4)-(2/3(6m+8))=0



Domain of the equation: 4(3m+4)!=0

m∈R





Domain of the equation: 3(6m+8))!=0

m∈R



We calculate fractions


(9m6/(4(3m+4)*3(6m+8)))+(-8m3/(4(3m+4)*3(6m+8)))=0



We calculate terms in parentheses: +(9m6/(4(3m+4)*3(6m+8))), so:

9m6/(4(3m+4)*3(6m+8))

We multiply all the terms by the denominator


9m6

We add all the numbers together, and all the variables

9m^6

We do not support empression: m^6

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