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3/4(3x+1)-(2x-1)=1/3(2x-6)+3
We move all terms to the left:
3/4(3x+1)-(2x-1)-(1/3(2x-6)+3)=0
Domain of the equation: 4(3x+1)!=0
x∈R
Domain of the equation: 3(2x-6)+3)!=0We get rid of parentheses
x∈R
3/4(3x+1)-2x-(1/3(2x-6)+3)+1=0
We calculate fractions
-2x+(9x2/(4(3x+1)*3(2x-6))+(-4x3/(4(3x+1)*3(2x-6))+1=0
We can not solve this equation
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