3/4(3x-5)=1/2(2x+5)

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Solution for 3/4(3x-5)=1/2(2x+5) equation: 



3/4(3x-5)=1/2(2x+5)

We move all terms to the left:

3/4(3x-5)-(1/2(2x+5))=0



Domain of the equation: 4(3x-5)!=0

x∈R





Domain of the equation: 2(2x+5))!=0

x∈R



We calculate fractions


(6x2/(4(3x-5)*2(2x+5)))+(-4x3/(4(3x-5)*2(2x+5)))=0



We calculate terms in parentheses: +(6x2/(4(3x-5)*2(2x+5))), so:

6x2/(4(3x-5)*2(2x+5))

We multiply all the terms by the denominator


6x2

We add all the numbers together, and all the variables

6x^2

Back to the equation:

+(6x^2)





We calculate terms in parentheses: +(-4x3/(4(3x-5)*2(2x+5))), so:

-4x3/(4(3x-5)*2(2x+5))

We multiply all the terms by the denominator


-4x3

We add all the numbers together, and all the variables

-4x^3

We do not support expression: x^3

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