3/4(3x-5)=1/3(2x+4)

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Solution for 3/4(3x-5)=1/3(2x+4) equation: 



3/4(3x-5)=1/3(2x+4)

We move all terms to the left:

3/4(3x-5)-(1/3(2x+4))=0



Domain of the equation: 4(3x-5)!=0

x∈R





Domain of the equation: 3(2x+4))!=0

x∈R



We calculate fractions


(9x2/(4(3x-5)*3(2x+4)))+(-4x3/(4(3x-5)*3(2x+4)))=0



We calculate terms in parentheses: +(9x2/(4(3x-5)*3(2x+4))), so:

9x2/(4(3x-5)*3(2x+4))

We multiply all the terms by the denominator


9x2

We add all the numbers together, and all the variables

9x^2

Back to the equation:

+(9x^2)





We calculate terms in parentheses: +(-4x3/(4(3x-5)*3(2x+4))), so:

-4x3/(4(3x-5)*3(2x+4))

We multiply all the terms by the denominator


-4x3

We add all the numbers together, and all the variables

-4x^3

We do not support expression: x^3

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