3/4(4-p)+3=1/6(2p+1)

Solution for 3/4(4-p)+3=1/6(2p+1) equation:

3/4(4-p)+3=1/6(2p+1)

We move all terms to the left:

3/4(4-p)+3-(1/6(2p+1))=0


Domain of the equation: 4(4-p)!=0

p∈R



Domain of the equation: 6(2p+1))!=0

p∈R


We add all the numbers together, and all the variables

3/4(-1p+4)-(1/6(2p+1))+3=0

We calculate fractions


(18p2/(4(-1p+4)*6(2p+1)))+(-4p0/(4(-1p+4)*6(2p+1)))+3=0


We calculate terms in parentheses: +(18p2/(4(-1p+4)*6(2p+1))), so:

18p2/(4(-1p+4)*6(2p+1))

We multiply all the terms by the denominator


18p2

We add all the numbers together, and all the variables

18p^2

Back to the equation:

+(18p^2)



We calculate terms in parentheses: +(-4p0/(4(-1p+4)*6(2p+1))), so:

-4p0/(4(-1p+4)*6(2p+1))

We multiply all the terms by the denominator


-4p0

We add all the numbers together, and all the variables

-4p

Back to the equation:

+(-4p)


We get rid of parentheses

18p^2-4p+3=0

a = 18; b = -4; c = +3;
Δ = b2-4ac
Δ = -42-4·18·3
Δ = -200
Delta is less than zero, so there is no solution for the equation