3/4(48-16z)=4(4+2z)

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Solution for 3/4(48-16z)=4(4+2z) equation: 



3/4(48-16z)=4(4+2z)

We move all terms to the left:

3/4(48-16z)-(4(4+2z))=0



Domain of the equation: 4(48-16z)!=0

z∈R



We add all the numbers together, and all the variables

3/4(-16z+48)-(4(2z+4))=0

We multiply all the terms by the denominator


-((4(2z+4)))*4(-16z+48)+3=0



We calculate terms in parentheses: -((4(2z+4)))*4(-16z+48), so:

(4(2z+4)))*4(-16z+48

We add all the numbers together, and all the variables

-16z+(4(2z+4)))*4(+48

Back to the equation:

-(-16z+(4(2z+4)))*4(+48)



We add all the numbers together, and all the variables

-(-16z+(4(2z+4)))*448+3=0

We move all terms containing z to the left, all other terms to the right

-(-16z+(4(2z+4)))*448=-3

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