3/4(4a+12)=21

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Solution for 3/4(4a+12)=21 equation: 



3/4(4a+12)=21

We move all terms to the left:

3/4(4a+12)-(21)=0



Domain of the equation: 4(4a+12)!=0

a∈R



We multiply all the terms by the denominator


-21*4(4a+12)+3=0

Wy multiply elements

-84a(4+3=0

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