3/4(4x+-6x)=75

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Solution for 3/4(4x+-6x)=75 equation: 



3/4(4x+-6x)=75

We move all terms to the left:

3/4(4x+-6x)-(75)=0



Domain of the equation: 4(4x+-6x)!=0

x∈R



We add all the numbers together, and all the variables

3/4(-2x)-75=0

We multiply all the terms by the denominator


-75*4(-2x)+3=0

Wy multiply elements

-300x(-+3=0

We use the square of the difference formula

-300x(-3=0

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