3/4(4x-12)-x=2(x+3)+3

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Solution for 3/4(4x-12)-x=2(x+3)+3 equation: 



3/4(4x-12)-x=2(x+3)+3

We move all terms to the left:

3/4(4x-12)-x-(2(x+3)+3)=0



Domain of the equation: 4(4x-12)!=0

x∈R



We add all the numbers together, and all the variables

-1x+3/4(4x-12)-(2(x+3)+3)=0

We multiply all the terms by the denominator


-1x*4(4x-12)-((2(x+3)+3))*4(4x-12)+3=0



We calculate terms in parentheses: -((2(x+3)+3))*4(4x-12), so:

(2(x+3)+3))*4(4x-12



Wy multiply elements

-4x^2(4-((2(x+3)+3))*4(4x-12)+3=0

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