3/4(5-12y)

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Solution for 3/4(5-12y) equation: 


y in (-oo:+oo)

(3/4)*(5-(12*y)) = 0

(3/4)*(5-12*y) = 0

3/4*(5-12*y) = 0

( 3/4 )

3/4 = 0

y belongs to the empty set

( 5-12*y )

5-12*y = 0 // - 5

-12*y = -5 // : -12

y = -5/(-12)

y = 5/12

y = 5/12

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