3/4(6x+10)+(13x-35)=180,x

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Solution for 3/4(6x+10)+(13x-35)=180,x equation: 



3/4(6x+10)+(13x-35)=180.x

We move all terms to the left:

3/4(6x+10)+(13x-35)-(180.x)=0



Domain of the equation: 4(6x+10)!=0

x∈R



We add all the numbers together, and all the variables

3/4(6x+10)+(13x-35)-(+180.x)=0

We get rid of parentheses

3/4(6x+10)+13x-180.x-35=0

We multiply all the terms by the denominator


13x*4(6x+10)-(180.x)*4(6x+10)-35*4(6x+10)+3=0

We add all the numbers together, and all the variables

13x*4(6x+10)-(+180.x)*4(6x+10)-35*4(6x+10)+3=0

Wy multiply elements

52x^2(6-(+180.x)*4(6x+10)-140x(6+3=0

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