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3/4(6x+5)=3/8(3-2x)
We move all terms to the left:
3/4(6x+5)-(3/8(3-2x))=0
Domain of the equation: 4(6x+5)!=0
x∈R
Domain of the equation: 8(3-2x))!=0We add all the numbers together, and all the variables
x∈R
3/4(6x+5)-(3/8(-2x+3))=0
We calculate fractions
(24x(-)/(4(6x+5)*8(-2x+3)))+(-12x6/(4(6x+5)*8(-2x+3)))=0
We calculate terms in parentheses: +(24x(-)/(4(6x+5)*8(-2x+3))), so:
24x(-)/(4(6x+5)*8(-2x+3))
We add all the numbers together, and all the variables
24x0/(4(6x+5)*8(-2x+3))
We multiply all the terms by the denominator
24x0
We add all the numbers together, and all the variables
24x
Back to the equation:
+(24x)
We calculate terms in parentheses: +(-12x6/(4(6x+5)*8(-2x+3))), so:
-12x6/(4(6x+5)*8(-2x+3))
We multiply all the terms by the denominator
-12x6
We add all the numbers together, and all the variables
-12x^6
We do not support expression: x^6
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