3/4(6x-12)=2x-17

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Solution for 3/4(6x-12)=2x-17 equation: 



3/4(6x-12)=2x-17

We move all terms to the left:

3/4(6x-12)-(2x-17)=0



Domain of the equation: 4(6x-12)!=0

x∈R



We get rid of parentheses

3/4(6x-12)-2x+17=0

We multiply all the terms by the denominator


-2x*4(6x-12)+17*4(6x-12)+3=0

Wy multiply elements

-8x^2(6+68x(6+3=0

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