3/4(7-6x)=9(-12x+15)

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Solution for 3/4(7-6x)=9(-12x+15) equation: 



3/4(7-6x)=9(-12x+15)

We move all terms to the left:

3/4(7-6x)-(9(-12x+15))=0



Domain of the equation: 4(7-6x)!=0

x∈R



We add all the numbers together, and all the variables

3/4(-6x+7)-(9(-12x+15))=0

We multiply all the terms by the denominator


-((9(-12x+15)))*4(-6x+7)+3=0



We calculate terms in parentheses: -((9(-12x+15)))*4(-6x+7), so:

(9(-12x+15)))*4(-6x+7

We add all the numbers together, and all the variables

-6x+(9(-12x+15)))*4(+7

Back to the equation:

-(-6x+(9(-12x+15)))*4(+7)



We add all the numbers together, and all the variables

-(-6x+(9(-12x+15)))*47+3=0

We move all terms containing x to the left, all other terms to the right

-(-6x+(9(-12x+15)))*47=-3

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