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3/4(8-12x)=3x-5
We move all terms to the left:
3/4(8-12x)-(3x-5)=0
Domain of the equation: 4(8-12x)!=0We add all the numbers together, and all the variables
x∈R
3/4(-12x+8)-(3x-5)=0
We get rid of parentheses
3/4(-12x+8)-3x+5=0
We multiply all the terms by the denominator
-3x*4(-12x+8)+5*4(-12x+8)+3=0
Wy multiply elements
-12x^2(-+20x(-+3=0
We use the square of the difference formula
-12x^2(-20x(-3=0
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