3/4(8-4k)=2k-9

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Solution for 3/4(8-4k)=2k-9 equation: 



3/4(8-4k)=2k-9

We move all terms to the left:

3/4(8-4k)-(2k-9)=0



Domain of the equation: 4(8-4k)!=0

k∈R



We add all the numbers together, and all the variables

3/4(-4k+8)-(2k-9)=0

We get rid of parentheses

3/4(-4k+8)-2k+9=0

We multiply all the terms by the denominator


-2k*4(-4k+8)+9*4(-4k+8)+3=0

Wy multiply elements

-8k^2(-+36k(-+3=0

We use the square of the difference formula

-8k^2(-36k(-3=0

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