3/4(8a-12)=27

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Solution for 3/4(8a-12)=27 equation: 



3/4(8a-12)=27

We move all terms to the left:

3/4(8a-12)-(27)=0



Domain of the equation: 4(8a-12)!=0

a∈R



We multiply all the terms by the denominator


-27*4(8a-12)+3=0

Wy multiply elements

-108a(8+3=0

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