3/4(8k-4)=-3+6k

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Solution for 3/4(8k-4)=-3+6k equation:



3/4(8k-4)=-3+6k
We move all terms to the left:
3/4(8k-4)-(-3+6k)=0
Domain of the equation: 4(8k-4)!=0
k∈R
We add all the numbers together, and all the variables
3/4(8k-4)-(6k-3)=0
We get rid of parentheses
3/4(8k-4)-6k+3=0
We multiply all the terms by the denominator
-6k*4(8k-4)+3*4(8k-4)+3=0
Wy multiply elements
-24k^2(8+12k(8+3=0

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