3/4(8m+12)+2/5(10m+20)=100

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Solution for 3/4(8m+12)+2/5(10m+20)=100 equation: 


m in (-oo:+oo)

(3/4)*(8*m+12)+(2/5)*(10*m+20) = 100 // - 100

(3/4)*(8*m+12)+(2/5)*(10*m+20)-100 = 0

3/4*(8*m+12)+2/5*(10*m+20)-100 = 0

3/4*(8*m+12)+2/5*(10*m+20)-100 = 0

10*m-100+17 = 0

10*m-83 = 0

10*m-83 = 0

10*m-83 = 0 // + 83

10*m = 83 // : 10

m = 83/10

m = 83/10

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