3/4(8q-12)+35/6=6+1/4q

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Solution for 3/4(8q-12)+35/6=6+1/4q equation: 



3/4(8q-12)+35/6=6+1/4q

We move all terms to the left:

3/4(8q-12)+35/6-(6+1/4q)=0



Domain of the equation: 4(8q-12)!=0

q∈R





Domain of the equation: 4q)!=0

q!=0/1

q!=0

q∈R



We add all the numbers together, and all the variables

3/4(8q-12)-(1/4q+6)+35/6=0

We get rid of parentheses

3/4(8q-12)-1/4q-6+35/6=0

We calculate fractions


432q/(4(8q-12)*4q*6)+(-24q8/(4(8q-12)*4q*6)+(560q^28/(4(8q-12)*4q*6)-6=0

We do not support eqpression: q^28

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