3/4(8x+28)=2/3(9x-3)

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Solution for 3/4(8x+28)=2/3(9x-3) equation: 



3/4(8x+28)=2/3(9x-3)

We move all terms to the left:

3/4(8x+28)-(2/3(9x-3))=0



Domain of the equation: 4(8x+28)!=0

x∈R





Domain of the equation: 3(9x-3))!=0

x∈R



We calculate fractions


(9x9/(4(8x+28)*3(9x-3)))+(-8x8/(4(8x+28)*3(9x-3)))=0



We calculate terms in parentheses: +(9x9/(4(8x+28)*3(9x-3))), so:

9x9/(4(8x+28)*3(9x-3))

We multiply all the terms by the denominator


9x9

We add all the numbers together, and all the variables

9x^9

We do not support expression: x^9

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