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3/4(8x+4)=2/3(6x-9
We move all terms to the left:
3/4(8x+4)-(2/3(6x-9)=0
Domain of the equation: 4(8x+4)!=0
x∈R
Domain of the equation: 3(6x-9)!=0We calculate fractions
x∈R
(9x6/(4(8x+4)*3(6x-9))+(-8x8/(4(8x+4)*3(6x-9))=0
We calculate terms in parentheses: +(9x6/(4(8x+4)*3(6x-9))+(-8x8/(4(8x+4)*3(6x-9)), so:
9x6/(4(8x+4)*3(6x-9))+(-8x8/(4(8x+4)*3(6x-9)
We calculate fractions
(9x6*(4(8x+4)*3(6x-9))/((4(8x+4)*3(6x-9))*(4(8x+4)*3(6x-9))+((-8x8*(4(8x+4)*3(6x-9)))/((4(8x+4)*3(6x-9))*(4(8x+4)*3(6x-9))
We calculate terms in parentheses: +(9x6*(4(8x+4)*3(6x-9))/((4(8x+4)*3(6x-9))*(4(8x+4)*3(6x-9))+((-8x8*(4(8x+4)*3(6x-9)))/((4(8x+4)*3(6x-9))*(4(8x+4)*3(6x-9)), so:
9x6*(4(8x+4)*3(6x-9))/((4(8x+4)*3(6x-9))*(4(8x+4)*3(6x-9))+((-8x8*(4(8x+4)*3(6x-9)))/((4(8x+4)*3(6x-9))*(4(8x+4)*3(6x-9)
We can not solve this equation
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