3/4(8x-12)+4=4x+1/5(10x-25)

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Solution for 3/4(8x-12)+4=4x+1/5(10x-25) equation: 



3/4(8x-12)+4=4x+1/5(10x-25)

We move all terms to the left:

3/4(8x-12)+4-(4x+1/5(10x-25))=0



Domain of the equation: 4(8x-12)!=0

x∈R





Domain of the equation: 5(10x-25))!=0

x∈R



We calculate fractions


(15x1/(4(8x-12)*5(10x-25)))+(-(4x+4x8)/(4(8x-12)*5(10x-25)))+4=0



We calculate terms in parentheses: +(15x1/(4(8x-12)*5(10x-25))), so:

15x1/(4(8x-12)*5(10x-25))

We multiply all the terms by the denominator


15x1

We add all the numbers together, and all the variables

15x

Back to the equation:

+(15x)





We calculate terms in parentheses: +(-(4x+4x8)/(4(8x-12)*5(10x-25))), so:

-(4x+4x8)/(4(8x-12)*5(10x-25))

We add all the numbers together, and all the variables

-(+4x+4x^8)/(4(8x-12)*5(10x-25))

We multiply all the terms by the denominator


-(+4x+4x^8)

We do not support expression: x^8

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