3/4(8x-12)=1/5(10x+15)

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Solution for 3/4(8x-12)=1/5(10x+15) equation: 



3/4(8x-12)=1/5(10x+15)

We move all terms to the left:

3/4(8x-12)-(1/5(10x+15))=0



Domain of the equation: 4(8x-12)!=0

x∈R





Domain of the equation: 5(10x+15))!=0

x∈R



We calculate fractions


(15x1/(4(8x-12)*5(10x+15)))+(-4x8/(4(8x-12)*5(10x+15)))=0



We calculate terms in parentheses: +(15x1/(4(8x-12)*5(10x+15))), so:

15x1/(4(8x-12)*5(10x+15))

We multiply all the terms by the denominator


15x1

We add all the numbers together, and all the variables

15x

Back to the equation:

+(15x)





We calculate terms in parentheses: +(-4x8/(4(8x-12)*5(10x+15))), so:

-4x8/(4(8x-12)*5(10x+15))

We multiply all the terms by the denominator


-4x8

We add all the numbers together, and all the variables

-4x^8

We do not support expression: x^8

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