3/4(8x-20)+12=4x+3

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Solution for 3/4(8x-20)+12=4x+3 equation: 



3/4(8x-20)+12=4x+3

We move all terms to the left:

3/4(8x-20)+12-(4x+3)=0



Domain of the equation: 4(8x-20)!=0

x∈R



We get rid of parentheses

3/4(8x-20)-4x-3+12=0

We multiply all the terms by the denominator


-4x*4(8x-20)-3*4(8x-20)+12*4(8x-20)+3=0

Wy multiply elements

-16x^2(8-12x(8+48x(8+3=0

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