3/4(8x-20)-(3x+1)=10-10(4-x)

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Solution for 3/4(8x-20)-(3x+1)=10-10(4-x) equation: 



3/4(8x-20)-(3x+1)=10-10(4-x)

We move all terms to the left:

3/4(8x-20)-(3x+1)-(10-10(4-x))=0



Domain of the equation: 4(8x-20)!=0

x∈R



We add all the numbers together, and all the variables

3/4(8x-20)-(3x+1)-(10-10(-1x+4))=0

We get rid of parentheses

3/4(8x-20)-3x-(10-10(-1x+4))-1=0

We multiply all the terms by the denominator


-3x*4(8x-20)-((10-10(-1x+4)))*4(8x-20)-1*4(8x-20)+3=0



We calculate terms in parentheses: -((10-10(-1x+4)))*4(8x-20), so:

(10-10(-1x+4)))*4(8x-20



Wy multiply elements

-12x^2(8-((10-10(-1x+4)))*4(8x-20)-4x(8+3=0

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