3/4(8x-20)=6x+12=12x

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Solution for 3/4(8x-20)=6x+12=12x equation: 



3/4(8x-20)=6x+12=12x

We move all terms to the left:

3/4(8x-20)-(6x+12)=0



Domain of the equation: 4(8x-20)!=0

x∈R



We get rid of parentheses

3/4(8x-20)-6x-12=0

We multiply all the terms by the denominator


-6x*4(8x-20)-12*4(8x-20)+3=0

Wy multiply elements

-24x^2(8-48x(8+3=0

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