3/4(8z-12)=1/6(36z+12)

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Solution for 3/4(8z-12)=1/6(36z+12) equation: 



3/4(8z-12)=1/6(36z+12)

We move all terms to the left:

3/4(8z-12)-(1/6(36z+12))=0



Domain of the equation: 4(8z-12)!=0

z∈R





Domain of the equation: 6(36z+12))!=0

z∈R



We calculate fractions


(18z3/(4(8z-12)*6(36z+12)))+(-4z8/(4(8z-12)*6(36z+12)))=0



We calculate terms in parentheses: +(18z3/(4(8z-12)*6(36z+12))), so:

18z3/(4(8z-12)*6(36z+12))

We multiply all the terms by the denominator


18z3

We add all the numbers together, and all the variables

18z^3

We do not support ezpression: z^3

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