3/4(b+4)=2/3(b-4)

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Solution for 3/4(b+4)=2/3(b-4) equation: 



3/4(b+4)=2/3(b-4)

We move all terms to the left:

3/4(b+4)-(2/3(b-4))=0



Domain of the equation: 4(b+4)!=0

b∈R





Domain of the equation: 3(b-4))!=0

b∈R



We calculate fractions


(9bb/(4(b+4)*3(b-4)))+(-8bb/(4(b+4)*3(b-4)))=0



We calculate terms in parentheses: +(9bb/(4(b+4)*3(b-4))), so:

9bb/(4(b+4)*3(b-4))

We multiply all the terms by the denominator


9bb

Back to the equation:

+(9bb)





We calculate terms in parentheses: +(-8bb/(4(b+4)*3(b-4))), so:

-8bb/(4(b+4)*3(b-4))

We multiply all the terms by the denominator


-8bb

Back to the equation:

+(-8bb)



We get rid of parentheses

9bb-8bb=0

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