3/4(c-4)+5/4c-20=6c-3

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Solution for 3/4(c-4)+5/4c-20=6c-3 equation: 



3/4(c-4)+5/4c-20=6c-3

We move all terms to the left:

3/4(c-4)+5/4c-20-(6c-3)=0



Domain of the equation: 4(c-4)!=0

c∈R





Domain of the equation: 4c!=0

c!=0/4

c!=0

c∈R



We get rid of parentheses

3/4(c-4)+5/4c-6c+3-20=0

We calculate fractions


-6c+12c/(16c^2-64c)+(20cc/(16c^2-64c)+3-20=0

We calculate fractions

We do not support ecpression: c^3

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