3/4(d+12)=1/2(2d-6)

Solution for 3/4(d+12)=1/2(2d-6) equation:

3/4(d+12)=1/2(2d-6)

We move all terms to the left:

3/4(d+12)-(1/2(2d-6))=0


Domain of the equation: 4(d+12)!=0

d∈R



Domain of the equation: 2(2d-6))!=0

d∈R


We calculate fractions


(6d2/(4(d+12)*2(2d-6)))+(-4dd/(4(d+12)*2(2d-6)))=0


We calculate terms in parentheses: +(6d2/(4(d+12)*2(2d-6))), so:

6d2/(4(d+12)*2(2d-6))

We multiply all the terms by the denominator


6d2

We add all the numbers together, and all the variables

6d^2

Back to the equation:

+(6d^2)



We calculate terms in parentheses: +(-4dd/(4(d+12)*2(2d-6))), so:

-4dd/(4(d+12)*2(2d-6))

We multiply all the terms by the denominator


-4dd

Back to the equation:

+(-4dd)


We get rid of parentheses

6d^2-4dd=0