3/4(m+12)=21

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Solution for 3/4(m+12)=21 equation:



3/4(m+12)=21
We move all terms to the left:
3/4(m+12)-(21)=0
Domain of the equation: 4(m+12)!=0
m∈R
We multiply all the terms by the denominator
-21*4(m+12)+3=0
Wy multiply elements
-84m(m+3=0

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