3/4(n+6)=1/2(n-3)

Solution for 3/4(n+6)=1/2(n-3) equation:

3/4(n+6)=1/2(n-3)

We move all terms to the left:

3/4(n+6)-(1/2(n-3))=0


Domain of the equation: 4(n+6)!=0

n∈R



Domain of the equation: 2(n-3))!=0

n∈R


We calculate fractions


(6nn/(4(n+6)*2(n-3)))+(-4nn/(4(n+6)*2(n-3)))=0


We calculate terms in parentheses: +(6nn/(4(n+6)*2(n-3))), so:

6nn/(4(n+6)*2(n-3))

We multiply all the terms by the denominator


6nn

Back to the equation:

+(6nn)



We calculate terms in parentheses: +(-4nn/(4(n+6)*2(n-3))), so:

-4nn/(4(n+6)*2(n-3))

We multiply all the terms by the denominator


-4nn

Back to the equation:

+(-4nn)


We get rid of parentheses

6nn-4nn=0