3/4(s-4)=1/4(2s+24)

Solution for 3/4(s-4)=1/4(2s+24) equation:

3/4(s-4)=1/4(2s+24)

We move all terms to the left:

3/4(s-4)-(1/4(2s+24))=0


Domain of the equation: 4(s-4)!=0

s∈R



Domain of the equation: 4(2s+24))!=0

s∈R


We calculate fractions


(12s2/(4(s-4)*4(2s+24)))+(-4ss/(4(s-4)*4(2s+24)))=0


We calculate terms in parentheses: +(12s2/(4(s-4)*4(2s+24))), so:

12s2/(4(s-4)*4(2s+24))

We multiply all the terms by the denominator


12s2

We add all the numbers together, and all the variables

12s^2

Back to the equation:

+(12s^2)



We calculate terms in parentheses: +(-4ss/(4(s-4)*4(2s+24))), so:

-4ss/(4(s-4)*4(2s+24))

We multiply all the terms by the denominator


-4ss

Back to the equation:

+(-4ss)


We get rid of parentheses

12s^2-4ss=0