3/4(t-6)=9/t=20

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Solution for 3/4(t-6)=9/t=20 equation: 



3/4(t-6)=9/t=20

We move all terms to the left:

3/4(t-6)-(9/t)=0



Domain of the equation: 4(t-6)!=0

t∈R





Domain of the equation: t)!=0

t!=0/1

t!=0

t∈R



We add all the numbers together, and all the variables

3/4(t-6)-(+9/t)=0

We get rid of parentheses

3/4(t-6)-9/t=0

We calculate fractions


3t/(4t^2-24t)+(-36tt/(4t^2-24t)=0



We calculate terms in parentheses: +(-36tt/(4t^2-24t), so:

-36tt/(4t^2-24t

We multiply all the terms by the denominator


-36tt

Back to the equation:

+(-36tt)



We get rid of parentheses

3t/(4t^2-24t)-36tt=0

We multiply all the terms by the denominator


3t-36tt*(4t^2-24t)=0

We multiply parentheses

-144t^3+864t^2+3t=0

We do not support etpression: t^3

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