3/4(t-6)=9;t-20

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Solution for 3/4(t-6)=9;t-20 equation: 



3/4(t-6)=9t-20

We move all terms to the left:

3/4(t-6)-(9t-20)=0



Domain of the equation: 4(t-6)!=0

t∈R



We get rid of parentheses

3/4(t-6)-9t+20=0

We multiply all the terms by the denominator


-9t*4(t-6)+20*4(t-6)+3=0

Wy multiply elements

-36t^2(t+80t(t+3=0

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