3/4(x+)=1/3(x+27)

Solution for 3/4(x+)=1/3(x+27) equation:

3/4(x+)=1/3(x+27)

We move all terms to the left:

3/4(x+)-(1/3(x+27))=0


Domain of the equation: 4(x+)!=0

x∈R



Domain of the equation: 3(x+27))!=0

x∈R


We add all the numbers together, and all the variables

3/4(+x)-(1/3(x+27))=0

We calculate fractions


(9xx/(4(+x)*3(x+27)))+(-4x0/(4(+x)*3(x+27)))=0


We calculate terms in parentheses: +(9xx/(4(+x)*3(x+27))), so:

9xx/(4(+x)*3(x+27))

We multiply all the terms by the denominator


9xx

Back to the equation:

+(9xx)



We calculate terms in parentheses: +(-4x0/(4(+x)*3(x+27))), so:

-4x0/(4(+x)*3(x+27))

We multiply all the terms by the denominator


-4x0

We add all the numbers together, and all the variables

-4x

Back to the equation:

+(-4x)


We get rid of parentheses

9xx-4x=0

We add all the numbers together, and all the variables

-4x+9xx=0