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3/4(x+1)+1=1/2(x-2)5
We move all terms to the left:
3/4(x+1)+1-(1/2(x-2)5)=0
Domain of the equation: 4(x+1)!=0
x∈R
Domain of the equation: 2(x-2)5)!=0We calculate fractions
x∈R
(6xx/(4(x+1)*2(x-2)5))+(-4xx/(4(x+1)*2(x-2)5))+1=0
We calculate terms in parentheses: +(6xx/(4(x+1)*2(x-2)5)), so:
6xx/(4(x+1)*2(x-2)5)
We multiply all the terms by the denominator
6xx
Back to the equation:
+(6xx)
We calculate terms in parentheses: +(-4xx/(4(x+1)*2(x-2)5)), so:We get rid of parentheses
-4xx/(4(x+1)*2(x-2)5)
We multiply all the terms by the denominator
-4xx
Back to the equation:
+(-4xx)
6xx-4xx+1=0
We move all terms containing x to the left, all other terms to the right
6xx-4xx=-1
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