3/4(x+1)=1/2(x-3)

Solution for 3/4(x+1)=1/2(x-3) equation:

3/4(x+1)=1/2(x-3)

We move all terms to the left:

3/4(x+1)-(1/2(x-3))=0


Domain of the equation: 4(x+1)!=0

x∈R



Domain of the equation: 2(x-3))!=0

x∈R


We calculate fractions


(6xx/(4(x+1)*2(x-3)))+(-4xx/(4(x+1)*2(x-3)))=0


We calculate terms in parentheses: +(6xx/(4(x+1)*2(x-3))), so:

6xx/(4(x+1)*2(x-3))

We multiply all the terms by the denominator


6xx

Back to the equation:

+(6xx)



We calculate terms in parentheses: +(-4xx/(4(x+1)*2(x-3))), so:

-4xx/(4(x+1)*2(x-3))

We multiply all the terms by the denominator


-4xx

Back to the equation:

+(-4xx)


We get rid of parentheses

6xx-4xx=0