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3/4(x+1)=5/8(x-4)
We move all terms to the left:
3/4(x+1)-(5/8(x-4))=0
Domain of the equation: 4(x+1)!=0
x∈R
Domain of the equation: 8(x-4))!=0We calculate fractions
x∈R
(24xx/(4(x+1)*8(x-4)))+(-20xx/(4(x+1)*8(x-4)))=0
We calculate terms in parentheses: +(24xx/(4(x+1)*8(x-4))), so:
24xx/(4(x+1)*8(x-4))
We multiply all the terms by the denominator
24xx
Back to the equation:
+(24xx)
We calculate terms in parentheses: +(-20xx/(4(x+1)*8(x-4))), so:We get rid of parentheses
-20xx/(4(x+1)*8(x-4))
We multiply all the terms by the denominator
-20xx
Back to the equation:
+(-20xx)
24xx-20xx=0
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