3/4(x+4)=8-1/2(x-4)

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Solution for 3/4(x+4)=8-1/2(x-4) equation: 



3/4(x+4)=8-1/2(x-4)

We move all terms to the left:

3/4(x+4)-(8-1/2(x-4))=0



Domain of the equation: 4(x+4)!=0

x∈R





Domain of the equation: 2(x-4))!=0

x∈R



We calculate fractions


(6xx/(4(x+4)*2(x-4)))+(-(-4xx)/(4(x+4)*2(x-4)))=0



We calculate terms in parentheses: +(6xx/(4(x+4)*2(x-4))), so:

6xx/(4(x+4)*2(x-4))

We multiply all the terms by the denominator


6xx

Back to the equation:

+(6xx)





We calculate terms in parentheses: +(-(-4xx)/(4(x+4)*2(x-4))), so:

-(-4xx)/(4(x+4)*2(x-4))

We multiply all the terms by the denominator


-(-4xx)

We get rid of parentheses

4xx

Back to the equation:

+(4xx)

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