3/4(x-2)+9=4/5(x+4)

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Solution for 3/4(x-2)+9=4/5(x+4) equation: 



3/4(x-2)+9=4/5(x+4)

We move all terms to the left:

3/4(x-2)+9-(4/5(x+4))=0



Domain of the equation: 4(x-2)!=0

x∈R





Domain of the equation: 5(x+4))!=0

x∈R



We calculate fractions


(15xx/(4(x-2)*5(x+4)))+(-16xx/(4(x-2)*5(x+4)))+9=0



We calculate terms in parentheses: +(15xx/(4(x-2)*5(x+4))), so:

15xx/(4(x-2)*5(x+4))

We multiply all the terms by the denominator


15xx

Back to the equation:

+(15xx)





We calculate terms in parentheses: +(-16xx/(4(x-2)*5(x+4))), so:

-16xx/(4(x-2)*5(x+4))

We multiply all the terms by the denominator


-16xx

Back to the equation:

+(-16xx)



We get rid of parentheses

15xx-16xx+9=0

We move all terms containing x to the left, all other terms to the right

15xx-16xx=-9

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