3/4(x-4)+2(3-1/3x)=(x-5)

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Solution for 3/4(x-4)+2(3-1/3x)=(x-5) equation: 



3/4(x-4)+2(3-1/3x)=(x-5)

We move all terms to the left:

3/4(x-4)+2(3-1/3x)-((x-5))=0



Domain of the equation: 4(x-4)!=0

x∈R





Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

3/4(x-4)+2(-1/3x+3)-((x-5))=0

We multiply parentheses

3/4(x-4)-2x-((x-5))+6=0

We multiply all the terms by the denominator


-2x*4(x-4)-(((x-5)))*4(x-4)+6*4(x-4)+3=0



We calculate terms in parentheses: -(((x-5)))*4(x-4), so:

((x-5)))*4(x-4



Wy multiply elements

-8x^2(x-(((x-5)))*4(x-4)+24x(x+3=0

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