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x in (-oo:+oo)
(((3/4)*(x-5)^2)/3)*(2*x-1) = 0
(3/4*(x-5)^2*(2*x-1))/3 = 0
( 2*x-1 )
2*x-1 = 0 // + 1
2*x = 1 // : 2
x = 1/2
( 3/4 )
3/4 = 0
x belongs to the empty set
( x-5 )
x-5 = 0 // + 5
x = 5
x in { 1/2, 5, 5 }
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